In a diode detector , output circuit consists of ` R = 1 M omega and C = 1 pF`. Calculate the carrier frequency it can detect.

Answer

`v_(c) > > 1 MHz`

Explanation

Here , `RC = 10^(6) xx 10^(-12) = 10^(-6) s`
For demodulation , `(1)/( v_( c )) lt lt RC or v_( c ) gt gt 1//RC`
` v_( c ) gt gt (1)/( 10^(-6)) = 10^(6) Hz = 1 MHz`
` :. v_( c ) gt gt 1 MHz`