In a diode dtector , output circuit consists of a resistance of `5 M omega` and a capacitor of `100 pF`. Calculate the carrier frequency it can detect.

Answer

`v_(c) > > 2 kHz`

Explanation

Here , `R = 5 M omega = 5 xx 10^(6) ohm`,
`C = 100 pF = 100 xx 10^(-12) F = 10^(-10) F`
`RC = ( 5 xx 10^(6)) xx 10^(-10) = 5 xx 10^(-4)`
For demodulation ,
` v_( c ) gt gt (1)/( RC)`
`v_(c ) gt gt (1)/( 5 xx 10^(-4)) = (10000)/(5) = 2000`
Here `v_(c ) gt gt 2 xx 10^(3) Hz or 2 kHZ`