A T.V. tower has a height `100 m`. What is the population density around the T.V. tower if the population density around the T.V. tower if the total population covered is `50 lakh` ? Radius of earth ` = 6.4 xx 10^(6) m`.

Answer

` 1242.9 km^(-2)`

Explanation

Population covered `= rho xx pi d^(2) = rho pi 2 hR`
so , ` 50 xx 10^(5) = rho xx (22)/(7) xx 2 xx 100 xx 6.4 xx 10^(6)`
or ` rho = ( 5 xx 7)/( 22 xx 2 xx 100 xx 6.4) m^(-2)`
` = ( 5 xx 7)/( 22 xx 2 xx 100 xx 6.4) km^(-2) = 1242.9 km^(-2)`