An EM wave of maximum frequency 300 kHz and critical freqeuncy 100 kHz is to be transmitted to a height equal to 150 k. calculate the skip distance.

Options

A. 624km
B. 849km
C. 636km
D. 942km

Explanation

Here, `h=150km, v_("max")=300 kHz`.
`v_(c)=100 kHz`
skip distance `D_("skip")=2hsqrt(((v_("max"))/v_(c))^(2)-1)`
`2xx150sqrt(((300)/100)^(2)-1)` or `D_("skip")=2xx150xxsqrt(8)`
or `D_("skip")=300xx2sqrt(2)=600xx1.414=848.4`
`=849km`