Home
Class 12
PHYSICS
Find the expression for capacitance of a...

Find the expression for capacitance of a parallel plate capacitor when (i) a thin dielectric slab is inserted between the plates, (ii) a thin conducting slab is inserted between the plates.
or Explain the concept of electric potential energy. Derive an expression for potential energy of a system of two point charges. Generalise the expression for N discrete charge.

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • COMMUNICATION SYSTEMS

    PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos

  • COMMUNICATION SYSTEMS

    PRADEEP|Exercise Multiple Choice Question|4 Videos

  • ATOMS AND NUCLEI

    PRADEEP|Exercise Assertion- Reason type question 12|1 Videos

  • CURRENT ELECTRICITY

    PRADEEP|Exercise Problems for Practice (B)|2 Videos

Similar Questions

Explore conceptually related problems

Explain the conept of electric potential energy. Derive an expression for potential energy of a system of two point charges. Generalise the expression fo N discrete charges.

Explain why the capacitance of a parallel plate capacitor increases when a dielectric slab is introduced between the plates.

How will capacitance of a parallel plate capacitor change on inserting a metal slab partially between its plates?

Derive an expression for the capacitance of a parallel plate capacitor. How is the capacitance affected when a conducting slab is introduced in-between its plates? Explain.

What is a parallel plate capacitor? Obtain an expression for the capacitance of a parallel plate capacitor when a conducting slab is inserted between its plates.

Find an expression for the capacitance of a parallel plate capacitor when a dielectric slab of dielectric constant K and thickness t=(d)/(2) but the same area on the plates is inserted between the the capacitors plate. (d=separation between the plates)

The potential enery of a charged parallel plate capacitor is U_(0) . If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,