An incident ray `(L_1)` is reflected by the mirror `(L_2)` 3x + 4y = 5 and the equation of reflected ray `(L_3)` is x + y = 1 the equation of `(L_1)` is :

The equation of line l_(1) is y=2x+3 , and the equation of line l_(2) is y=2x-5.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24x+7y+5=0. Find the equation of mirrors.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24 x+7y+5=0. Find the equation of mirrors.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24 x+7y+5=0. Find the equation of mirrors.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24 x+7y+5=0. Find the equation of mirrors.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24 x+7y+5=0. Find the equation of mirrors.

The equation of line l_(1) is y=(5)/(2)x-4 , and the equation of line l_(2) is y=-(2)/(5)x+9 .

Consider a plane mirror P_(1) having equation as z=0. A ray of light emerging from the point P(1,2,3) and travelled along the line (x-1)/(3)=(y-2)/(2)=(z-3)/(1) get reflected from the plane mirror P_(1) and the reflected line is denoted by L_(2) .The equation of the line L_(2), is