A position charge q is placed at a distance of 4R above the centre of a disc of radius R. The magnitude of flux through the disc is `phi`. Now a hemispherical shell of radius R is placed over the disc such that it forms a closed surface. The flux through the curved surface (taking direction of area vector along outward normal as positive), is -

A charge Q is placed at a distance of 4R above the centre of a disc of radius R. The magnitude of flux through the disc is phi . Now a henispherical shell of radius R is placed over the disc such that it forms a closed surface. The flux through the curved taking direction of area vector along outward normal as positive , is

A positive point charge Q is placed (on the axis of disc) at a distance of 4 R . Above the centre of a disc of radius R as shown in situation I. the magnitude of electric flux through the disc is (phi) . Now a hemis pherical shell of radius R is placed over the disc. such that it forms a closed surface as shown in situation II. The flux through the curved suface in situation II taking direction of area vector along outward normal as positive is

A point charge q is placed at a distance d form the center of circular disc of radius R . Find electric flux through the disc due to that charge

A point charge q is placed at a distance d from the centre of a circular disc of radius R. Find electric flux flowing through the disc due to that charge

A hemispherical surface of radius R is kept in a uniform electric field E as shown in figure. The flux through the curved surface is

A hemispherical body of radius R is placed in a uniform electric field E. The flux linked with the curved surface if the field is perpendicular to base