In Region of Electric field Given by `vec(E)=(Ax-B)hat(I)`. Where `A=20` unit and `B=10` unit. If Electric potential at `x=1m` is `v_(2)`. Then `v_(1)-v_(2)` is equal to

In Region of Electric field Given by vec(E)=(Ax-B)hat(I) . Where A=20 unit and B=10 unit. If Electric potential at x=1m is v_(1) and at x=-5m is v_(2) . Then v_(1)-v_(2) is equal to

The electric field in a region of space is given as bar(E)=(5xhat i-2hat j) .Potential at point x=1 y=1 is V_(1) and potential at point (x=2 y=3) is V_(2) .Then V_(1) -V_(2) is equal to

The electric field in a region of space is given as bar(E)=(5xhat i-2hat j) .Potential at point x =1 y =1 is V_(1) and potential at point x =2 y =3 is V_(2) .Then V_(1)-V_(2) is equal to

The electric field in a region is given by oversettoE=(Ax+B)hati Where E is in NC^(-) and x is in metres. The values of constants are A=20SI Unit and B==10SI unit. If the potential at x=1 is V_(1) and that at x=-5 is V_(2) then V_(1)-V_(2) is:

An electric field is represented by vecE = "Ax" hati where A = 10 (V)/(m^(2)) . Find the potential of the origin with respect to the point (10,20) m.

Assume that an electric field vec(E) = 30 x^(2) hat(i) exists in space. Then the potential differences V_(A) - V_(0) where V_(0) is the potential at the origin and V_(A) , the potential at x = 2m is

Assume than an electric field vec(E ) = 30 x^(2)hat(i) exists in space. Then the potential difference V_(A) - V_(O) , where V_(O) is the potential at the origin and V_(A) the potential at x = 2 m is

An electric field vec(E)=B x hat(i) exists in space, where B = 20 V//m^(2) . Taking the potential at (2m, 4m) to be zero, find the potential at the origin.

An electric field vec(E)=B x hat(i) exists in space, where B = 20 V//m^(2) . Taking the potential at (2m, 4m) to be zero, find the potential at the origin.