`(2x-1)/3 -(6x-2)/5 =1/3`

(4x+1)/(3)+(2x-1)/(2)=6+(3x-7)/(5)

(x-1)/(3)+(2x+5)/(6)=(3x-6)/(9)-(2x-5)/(2)

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)

If l=int((2x-3)^(1/2))/((2x-3)^(1/3)+1)dx=3[(1)/(7)(2x-3)^(7/6)-(1)/(5)(2x-3)^(5/6)+(1)/(3)(2x-3)^(1/2)-(2x-3)^(1/6)+g(x)]+c then g(x) is equal to

Evaluate the limits: lim_(xrarr1/2)(8x^3-1)/(6x^2-5x+1)

Take away : 6/5x^2-4/5x^3+5/6+3/2x from (x^3)/3-5/2x^2+3/5x+1/4

Add :5x^(2)-(1)/(3)x+(5)/(2),-(1)/(2)x^(2)+(1)/(2)x-(1)/(3) and -2x^(2)+(1)/(5)x-(1)/(6)

3+(x)/(4)=(1)/(2)(4-(x)/(3))-(5)/(6)+(1)/(3)(11-(x)/(2))