the wavelength of spectral line in the lyman series of a H-atom is `1028 Å`. If instead of hydrogen, we consider deuterium then shift in the wavelength of this line be `(m_p=1860m_e)`

The first four spectral lines in the Lyman series of a H-atom are lambda=1218Å, 1028Å,974.3Å and 951.4Å . If instead of Hydrogen, we consider Deuterium, calculate the shift in the wavelength of these lines.

The first four spectral lines in the Lyman series of a H-atom are lambda=1218Å, 1028Å,974.3Å and 951.4Å . If instead of Hydrogen, we consider Deuterium, calculate the shift in the wavelength of these lines.

Calculate the wavelength of spectral line in lyman series corresponding to n2 = 3.

The wavelength of the first spectral line of the Lyman series of hydrogen spectrum is

Calculate the wavelength of spectral line in Lyman series corresponding to n_2 = 3 .

Calculate the wavelength of the first spectral line in the corresponding Lyman series of the hydrogen atom.

Calculate the wavelength of the spectral line with n_(2)=3 in Lyman series of hydrogen atom.

The shortest wavelength spectral line in the brackett series of the spectrum of atomic hydrogen is the transition :

The shortest wavelength spectral line in the brackett series of the spectrum of atomic hydrogen is the transition :