A cyclist moves around a circular path of radius `40sqrt3 m` with a speed of `20 m//s`. He must lean inwards at an angle `theta` with the vertical such that `tan theta` is equal to

A cyclist moves around a circular path of radius 39.2sqrt(3) metre with a speed of 19.6ms^(-1) '. He must lean inwards at an angle theta with the vertical such that tantheta is

A cyclist moves around a circular path of radius 39.2sqrt(3) metre with a speed of 19.6ms^(-1) '. He must lean inwards at an angle theta with the vertical such that tantheta is

A cyclist goes round a circular track of radius 20sqrt3 m at a speed of 14 m/s. What is the inclination to the vertical ?

A cyclist goes round a circular track of radius 20sqrt3 m at a speed of 24sqrt3 ms^(-1) . What is the inclination to the vertical ?

A cyclist goes round a circular path of radius 20.0 m with a speed of 14 m s^-1 .Find the angle through which his cycle makes with vertical. (g=9.8 ms ^-2) .

A car is moving along a circular path of radius 20 m with a speed of 40 km cdot h^(-1) . Find its angular velocity.

A car moves a circular path of radius 20 m in 50 s with a uniform speed. Find the speed.

A cyclist is moving on a circular track of radius 80 m with a velocity of 72 km//h .He leans from the direction through an angle of :

When a cyclist negotiates a circular path of radius .r. with velocity .v., making an angle theta with the vertical, show that tantheta=v^(2)/(rg) .

A cyclist with combined mass 80 kg going around a curved road with a uniform speed 20 m//s . He has to bend inward by an angle theta = tan^(-1) (0.50) with the verticle , then the force of friction between road surface and tyres will be (g=10m//s^(2)