A shpere of radius `r` carries a surface charge a density `sigma = ar`, where a is a constant, vector and `r` is radius vector of a point of the sphere ralative to its centre. Find the electric field strength vector at the centre relative at the centrre of the sphere.

A sphere of radius R has a charge density sigma . The electric intensity at a point at a distance r from its centre is

A hollow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre

The surface density on a copper sphere is sigma . The electric field strength on the surface of the sphere is

The surface density on the copper sphere is 'sigma'. The electric field strength on the surface of the sphere is :

The surface density on a copper sphere is sigma . The electric field strength on the surface of the sphere is

Find the electric field strength vector at the centre of a ball of raiduius R with volume charge density rho implies ar , where a is a constant vector, and r is a radius vector drawn from the ball's centre.

Find the electric field strength vector if the potentail of this field has the form varphi = ar , where is a constatn vector, and r is the radius vector of point of the field.

A hallow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre:

A hallow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre:

A spherical charged conductor has surface charge density sigma .The intensity of electric field and potential on its surface are E and V .Now radius of sphere is halved keeping the charge density as constant .The new electric field on the surface and potneial at the centre of the sphere are