The area of the region in the xy-plane defined by the inequalities `x-2y^2>=,1-x-|y|>=0` is

Determine the region in the plane determined by the inequalities. x - 2y ge 0, 2x - y le - 2, x ge 0, y ge 0.

Determine the region in the plane determined by the inequalities. y ge 2x, -2x + 3y le 6.

Determine the region in the plane determined by the inequalities y ge 2x and -2x + 3y le 6 .

Determine the region in the plane determined by the inequalities. 2x + y ge 8, x + 2y ge 8, x + y le 6.

The region of xy-plane represented by the inequations x>=0,y>=0,2x+y<=30,x+2y<=30 is

Construct the region represented by the inequations x+y<=3 and x-y<=2

The area of the region {(x,y): xy le 8,1 le y le x^(2)} is :

The area of the region {(x,y): xy le 8,1 le y le x^(2)} is :

The area of the region whose boundaries are defined by the curves y=2 cos x, y=3 tan x, and the y-axis is

The area of the region whose boundaries are defined by the curves y=2 cos x, y=3 tan x, and the y-axis is