If mass `%` of oxygen in monovalent metal 'M' carbonate `(M_(2)CO_(3))` is `48%`, find atomic mass of metal ? .

If mass % of oxygen in monovalent metal carbonate is 48% ,then find the number of atoms of metal present in 5mg of this metal carbonate sample is ( N_(A) = 6.0 xx 10_(23) )

If mass % of oxygen in monovalent metal carbonate is 48% , then the number of atoms of metal present in 5mg of this metal carbonate sample is:

A metal nitride M_(3)N_(2) contains 28 % of nitrogen. The atomic mass of metal M is

A metal nitride M_(3)N_(2) contains 28 % of nitrogen. The atomic mass of metal M is

A metal M of equivalent mass E forms an oxide of molecular formula M_(x)O_(y) . The atomic mass of the metal is given by the correct equation.