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If 0.30 mol of zinc are added to 0.52 mo...

If 0.30 mol of zinc are added to 0.52 mol of HCl, the moles of `H_(2)` formed are

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Zinc and hydrochloric acid react according to the reaction: Zn_((s))+2HCl_((aq.))rarr ZnCl_(2(aq.))+H_(2(g)) If 0.30 mole of Zn are added to hydrochloric acid containing 0.52 mole HCl , how many moles of H_(2) are produced?

Zinc and hydrochloric acid react according to the reaction: Zn_((s))+2HCl_((aq.))rarr ZnCl_(2(aq.))+H_(2(g)) If 0.30 mole of Zn are added to hydrochloric acid containing 0.52 mole HCl , how many moles of H_(2) are produced?

Zinc and hydrochloric acid react according to the reaction: Zn_((s))+2HCl_((aq.))rarr ZnCl_(2(aq.))+H_(2(g)) If 0.30 mole of Zn are added to hydrochloric acid containing 0.52 mole HCl , how many moles of H_(2) are produced?

0.30 mole Zinc are added to hydrochloric acid containing 0.52 mole HCl. How many moles of H_2 are produced? Zn_(s) + HCl_(aq) rarr ZnCl_(2(aq)) + H_(2(g))

At S.T.P. 0.50 mol of H_(2) gas and 1.-0 mol of He gas