In the compound `Na_(2)S_(2)O_(3)`, the oxidation state of sulphur is:

When Cl_(2) is treated with Na_(2)S_(2)O_(3) the oxidation state of sulphur in the product is x .When I_(2) is treated with Na_(2)S_(2)O_(3) the oxidation state of sulphur in the product is y what is (x+2y)/(11)

The oxidation state of sulphur in Na_(2)S_(4)O is

The oxidation state of sulphur in H_(2)S_(2)O_(7) is

The oxidation state of sulphur in Na_(2)S_(4)O_(6) is

When \(Cl_{2}\) is treated with \(Na_{2}S_{2}O_{3}\) the oxidation state of sulphur in the product is x .When \(I_{2}\) is treated with \(Na_{2}S_{2}O_{3}\) the oxidation state of sulphur in the product is y. What is [x+2y/11]

In polythionic acid, H_(2)S_(x)O_(6) (x=3 to 5) the oxidation state(s) of sulphur is/are