The minimum positive values of `x` and `y` for which `x+y=pi/2` and `sec x+ sec y=2sqrt2` has solution is

The smallest positive values of x and y which satisfy tan (x-y)=1, sec (x+y)=2//sqrt(3) are

The smallest positive values of x and y which satisfy "tan" (x-y) =1, "sec" (x+y) = (2)/(sqrt(3)) , are

The smallest positive values of x and y which satisfy "tan" (x-y) =1, "sec" (x+y) = (2)/(sqrt(3)) , are

If 0 lt x lt pi/2 and sec x = cosec y , then the value of sin (x + y) is

The minimum value of sec x, x in [(2pi)/(3),pi] is ……….

The values of x in [-2 pi,2 pi], for which the graph of the function y=sqrt((1+sin x)/(1-sin x))-sec x and y=-sqrt((1-sin x)/(1+sin x)) coincide are

If x+y=2 alpha then minimum value of sec x+sec y is (x,y in(0,(pi)/(2)))( a) 2cos alpha (b) cos2 alpha(c)2sec alpha

If y = sqrt(sec 2x ) then y _(2) =

The curve y=sec x tan x+2tan x-sec x and the line y=2 intersect in

Maximum value of y=sec x "in" (pi//2,3pi//2) is