In the circuit shown below the resistance of the galvanometer is `20Omega`. In which case of the following alternatives are the currents arranged strictly in the decreasing order

In figure, the resistance of galvanometer G is 50 ohm and the battery is ideal. Of the following alternatives, in which case, are the currents arranged strictly in the order of decreasing magnitudes with the larger coming earlier-

If the resistance of the galvanometer G is 15 Omega , then current through the galvanometer will be

In the circuit shown, the current in 3Omega resistance is

In the circuit shown, the current in 3Omega resistance is

In the circuit shown above the current through the 15 Omega resistance is

In the circuit shown the current through 2 Omega resistance is

In the circuit shown,the coil resistance of the ammeter is 1Omega while that of the voltmeter is 20Omega .The main branch current is (19)/(20) A.The reading of voltmeter in volt is

In the circuit shown the currents in 4 Omega and 8 Omega resistances are

" the circuit shown,the coil resistance of the ammeter is "1Omega" while that of the voltmeter is "20Omega" .The main branch current is "(19)/(20)" A.The reading of voltmeter in volt is "