यदि `A=diag [a, b, c]` तब दर्शाइए की
`A^(n)=diag [a^(n), b^(n), c^(n)] AA n in N`

If A=diag[a,b,c] then show that A^(n)=diag[a^(n),b^(n),c^(n)] for all n in N

If A = diag [{:(a,b,c):}] , then show that A^(n)="diag"[{:(a^(n),b^(n),c^(n)):}],AAn in N .

If A=diag(abc), show that A^(n)=diag(a^(n)b^(n)c^(n)) for all positive integer n.

If A=diag(abc), show that A^(n)=diag(a^(n)b^(n)c^(n)) for all positive integer n .

If ""^(n)C_(a)= ""^(n)C_(b) ' then find n.

If diagA=[a_(1),a_(2),a_(3)] , then for any integer n ge 1 show that A^(n) = diag[a_(1)^(n), a_(2)^(n), a_(3)^(n)]

Statement 1: if D= diag [d_1, d_2, ,d_n] ,then D^(-1)= diag [d_1^(-1),d_2^(-1),...,d_n^(-1)] Statement 2: if D= diag [d_1, d_2, ,d_n] ,then D^n= diag [d_1^n,d_2^n,...,d_n^n]

If a,b,c,d are in G.P., prove that (a^(n) + b^(n)), (b^(n) + c^(n)), (c^(n) + d^(n)) are in G.P.