in an `AP , S_p=q , S_q=p` and `S_r` denotes the sum of the first `r` terms. Then `S_(p+q)=`

If in an A.P. S_(n) = qn^(2) and S_(m) = qm^(2) , where S_(r ) denotes the sum of r terms of the A.P. , then S_(q) equals :

If in an AP, S_(n)= q n^(2) and S_(m)= qm^(2) , where S_(r ) denotes the sum of r terms of the AP, then S_(q) equals to,

If in an A.P. S_n=n^2q\ a n d\ S_m=m^2q ,\ w h e r e\ S_r denotes the sum of r terms of the A.P., then S_q equals a. (q^3)/2 b. m n q c. q^3 d. (m^2+n^2)q

If S_(n) = nP + (n (n - 1))/(2) Q where S_n denotes the sum of the first n terms of an A.P. , then the common difference is

If in an A.P.S_(n)=n^(2)q and S_(m)=m^(2)q, where S_(r) denotes the sum of r terms of the A.P.then S_(q) equals (q^(3))/(2) b.mnq c.q^(3) d.(m^(2)+n^(2))q

In an AP,S_(p)=q,S_(q)=p. Then S_(p+q) is equal to :

If a,b,c be respectively the sum of first p,q,r terms of an A.P. then a/p(q-r) + b/q(r-p) + c/r(p-q) equals :

In the figure ABCD iś a parallelogram. dotP, Q, R and S are the midpoint of the sides of the parallelogram. Prove that P Q=R S and Q R=P S .

If P Q R S is a square, then write the measure of /_S R P

If P Q R S is a square, then write the measure of /_S R P