A current of 2.0 ampere passes through a cell of e.m.f. 1.5 volts having internal resistance of 0.15 ohm. The potential difference measured, in volts, across both the ends of the cell will be

A current of 2.0 A passes through a cell of emf 1.5 V having internal resistance of 0.15 Omega . The potential difference (measured in volt) across both the terminals of the cell is

The e.m.f. of a cell is E volts and internal resistance is r ohm. The resistance in exteral circuit is also r ohm. The p.d across the cell will be

A storage battery has e.m.f. 15 volts and internal resistance 0.05 ohm . Its terminal voltage when it is delivering 10 ampere is

A current of two amperes is flowing through a cell of e.m.f. 5 volts and internal resistance 0.5 ohm from negative to positive electrode. If the potential of negative electrode is 10 V , the potential of positive electrode will be

A current of two amperes is flowing through a cell of e.m.f. 5 volts and internal resistance 0.5 ohm from negative to positive electrode. If the potential of negative electrode is 10 V , the potential of positive electrode will be

A current of two amperes is flowing through a cell of e.m.f. 5 volts and internal resistance 0.5 ohm from negative to positive electrode. If the potential of negative electrode is 10 V , the potential of positive electrode will be

Choose correct alternative. Two resistance of 3 Omega and 2 Omega are connected in series to a cell of emf 3 volt and internal resistance of 1 Omega . The potential difference across 3 Omega resistance will be A. 1 volt B. 0.5 volt C. 1.5 volt D. 2 volt

Two cells A and B ofe.m.f. 2V and 1.5V respectively, are connected as shown in figure through an external resistance 10 ohm. The internal resistance of each cell is 5 ohm. The potential difference E_(A) and E_(B) across the terminals of the cells A and B respectively are

The emf of a cell is E volt and internal resistance is r ohm. It resistance in the external circuit is r ohm, the p.d. across the cell will be