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Show that the Modulus Function f" ": R->...

Show that the Modulus Function `f" ": R->R ,` given by `f" "(x)" "=" "|" "x" "|` , is neither one-one nor onto, where `|" "x" "|` is x, if x is positive or 0 and `|" "x" "|` is `" "x` , if x is negative.

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