" If "alpha" and "beta" are acute angles satisfying "cos2 alpha=(3cos2 beta-1)/(3-cos2 beta)," then "tan alpha

cos2alpha=(3cos2beta-1)/(3-cos2beta) , then tan alpha=

cos 2 alpha =(3 cos 2 beta -1)/( 3-cos 2 beta), then tan alpha=

cos 2 alpha =(3 cos 2 beta -1)/( 3-cos 2 beta), then tan alpha=

alpha and beta are acute angles and cos2 alpha=(3cos2 beta-1)/(3-cos2 beta) then tan alpha cot beta=

If alpha and beta be acute angles and cos2 alpha=(3cos2 beta-1)/(3-cos2 beta), then tan alpha is :

If alpha, beta are acute angles and cos 2 alpha=(3 cos 2 beta-1)/(3-cos 2 beta) then

If cos2alpha=(3cos2beta-1)/(3-cos2beta) , then tan alpha is equal to

alpha and beta are acute angles and cos2alpha = (3cos2beta-1)/(3-cos2beta) then tan alpha cot beta =

If alpha and beta are acute angles and cos2 alpha=(3cos2 beta-1)/(3-cos2 beta). Prove that :tan alpha=sqrt(2)tan beta