If `a_1,a_2,a_3` are 3 positive consecutive terms of a GP with common ratio K . then all the values of K for which the inequality `a_3>4a_2-3a_1`, is satisfied

If a_1,a_2,a_3(a_1 gt0) are in G.P with common ratio r, then the value of r , for which the inequality 9 a_1+5a_3le14a_2 holds, can not lie in the interval.

If a_1, a_2, a_3(a_1>0) are three successive terms of a G.P. with common ratio r , for which a_3>4a_2-3a_1 holds is given by

If a_1, a_2, a_3(a_1>0) are three successive terms of a G.P. with common ratio r , for which a_3>4a_2-3a_1 holds true is given by a. 1ltrlt-3 b. -3ltrlt-1 c. r gt3 or rlt1 d. none of these

The average of a_1, a_2, a_3, a_4 is 16. Half of the sum of a_2, a_3, a_4 is 23. What is the value of a_1

If a_1, a_2, a_3,...a_20 are A.M's inserted between 13 and 67 then the maximum value of the product a_1 a_2 a_3...a_20 is

If a_1,a_2,a_3,....a_n are positive real numbers whose product is a fixed number c, then the minimum value of a_1+a_2+....+a_(n-1)+3a_n is

If a_1,a_2,a_3,....a_n are positive real numbers whose product is a fixed number c, then the minimum value of a_1+a_2+....+a_(n-1)+3a_n is

If a_1,a_2,a_3,....a_n are positive real numbers whose product is a fixed number c, then the minimum value of a_1+a_2+....+a_(n-1)+3a_n is

If a_1,a_2, a_3, a_4 be the coefficient of four consecutive terms in the expansion of (1+x)^n , then prove that: (a_1)/(a_1+a_2)+(a_3)/(a_3+a_4)=(2a_2)/(a_2+a_3)dot

If a_1,a_2, a_3, a_4 be the coefficient of four consecutive terms in the expansion of (1+x)^n , then prove that: (a_1)/(a_1+a_2)+(a_3)/(a_3+a_4)=(2a_2)/(a_2+a_3)dot