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In a circle with centre 'O' PA and PB ar...

In a circle with centre `'O' PA and PB` are two chords. PC is the chord that bisects the angle APB.The tangent to the circle at C is drawn meeting PA and PB extended at Q and R respectively. If `QC = 3, QA = 2 and RC = 4`, then length of RB equals:

Text Solution

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In`triangle PQC`
(PQ)(AQ)=QC^2
PQ*2=9
PQ=9/2
`Sintheta= (QC)/(PQ)=(RC)/(PR)`
=`3/(9/2)=4/(PR)`
=PR=6
In`trianglePCR`
...
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