In the arrangement shown in figure the wall is smooth and friction coefficient between the blocks is `mu = 0.1`. A horizontal force `F = 1000 N` is applied on the `2kg` block. The wrong statement is :

The friction coefficient between the blocks is mu . If force F is applied on the lower block , analyse motion of two blocks.

In the arrangement shown in figure, coefficient of friction between the two blocks is mu=1//2 . The force of friction acting between

2gk block is kept on 1kg block as shown . The friction between 1kg block and fixed surface is absent and the coefficient of friction between 2kg block is mu=0.1 . A constant horizontal force F=4N is applied on 1kg block. If the work done by the friction on 1 kg block in 2s is -X J , then find X . Take g=10m//s^(2) .

2gk block is kept on 1kg block as shown . The friction between 1kg block and fixed surface is absent and the coefficient of friction between 2kg block is mu=0.1 . A constant horizontal force F=4N is applied on 1kg block. If the work done by the friction on 1 kg block in 2s is -X J , then find X . Take g=10m//s^(2) .

A plank of mass 10kg rests on a smooth horizontal surface. Two blocks A and B of masses m_(A)=2kg and m_(B)=1kg lies at a distance of 3m on the plank as shown in the distance of 3m on the plank as shown in the figure. The friction coefficient between the blocks and plank are mu_(A)=0.3 and mu_(B)=0.1 . Now a force F = 15 N is applied to the plank in horizontal direction. Find the time after which block A collides with B.

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

A block of mass m=4kg is placed oner a rough inclined plane as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . A force F=10N is applied on the block at an angle of 30^(@) .

On a smooth table two blocks of masses 2.5kg and 1.5kg are placed one over the other as shown in figure. If the coefficient of static friction between two blocks is 0.2, the maximum horizontal force to be applied on the lower block so that the two blocks move together is (g = ms^(-2) )