`n` का मान ज्ञात कीजिए यदि `""^(2n)C_(3):""^(n)C_(2)=44:3`

Options

A. `n = 6`
B. `n = 5`
C. `n = 4`
D. `n = 3`

Answer

A

Explanation

प्रश्नानुसार `""^(2n)C_(3):""^(n)C_(2)= 44:3`
`rArr (""^(2n)C_(3))/(""^(n)C_(2)) = 44/3`
`rArr (((2n)!)/(3!(2n-3)))/((n!)/(2!(n-2))) = 44/3rArr ((2n)!2!(n-2)!)/(3!(2n-3)!n!)= 44/3`
`rArr (2n(2n-1)(2n-2))/(3n(n-1))= 44/3 rArr (2(2n-1)2)/(3) = 44/3`
`rArr 2n - 1 = 11 rArr n = 6`