निम्नलिखित फलन का अवलंकन गुणांक ज्ञात कीजिएः
`-9" "5sqrt(x^(-9))`

Explanation

माना `-9" "5sqrt(x^(-9))=-9(x^(-9))^(1//5)=-9x^(-9//5)`
`therefore (dy)/(dx)=(d)/(dx)(-9x^(-9//5))`
`=-9(d)/(dx)x^(-9//5)=-9xx(-(9)/(5))x^(-(9)/(5)-1)=(81)/(5)x^(-14//5)`