`[(e^(x)(x-1))/(x+1)]` का अवकलन गुणांक ज्ञात कीजिएः

Explanation

यदि `Y=(e^(x)(x-1))/(x+1)`
तब `(dy)/(dx)=((x+1)(d)/(dX)[e^(x)(x-1)]-e^(x)(x-1)(d)/(dx)(x+1))/((x+1)^(2))`
`=((x+1)[e^(x)(x-1)+e^(x)(1-0)]-e^(x)(x-1)(1+0))/((x+1)^2)`
`=((x+1)e^(x)[x-1+1]-e^(x)(x-1))/((x+1)^(2))`
`=(e^(x)[(x+1)x-(x-1)])/((x+1)^(2))`
`=(e^(x)[x^(2)+1-x+1])/((x+1)^2)`
`=(e^(x)(x^(2)+1))/((x+1)^(2))`