यदि `y=((a)/(x))^(m)+((x)/(b))^(n)` तब `(dy)/(dx)` का मान ज्ञात कीजिएः।

Answer

`-ma^(m)m^(-m-1)+(n)/(b^(n))x^(n-1)`

Explanation

`(dy)/(dx)=(d)/(dx)(y)=(d)/(dx)[((a)/(x))^(m)+((x)/(b))^(n)]`
`=a^(m)(d)/(dx)(x^(-m))+(1)/(b^(n)) (d)/(dx)(x^(n))=a^m,(-mx^(-m-1))+(1)/(b^(n))nx^(n-1)=-ma^(m)x^(-m-1)+(nx^(n-1))/(b^(n))`