Tangents are drawn from the origin to curve `y=sinxdot` Prove that points of contact lie on `y^2=(x^2)/(1+x^2)`

Tangents are drawn from the origin to curve y=sin x. Prove that points of contact lie on y^(2)=(x^(2))/(1+x^(2))

Tangents are drawn from the origin to the curve y=cos X . Their points of contact lie on

If tangents are drawn from the origin to the curve y= sin x , then their points of contact lie on-

Tangents are drawn from the origin to the curve y=cos X. Their points of contact lie on

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^2y^2=(x^2-y^2) .

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^(2) y^(2) = (x^(2) - y^(2))

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^(2) y^(2) = (x^(2) - y^(2))

3.(1) x + y = 0(2) x - y = 0If tangents are drawn from the origin to the curve y = sin x, then their points of contact lie on the curve(3) x2 - y2 = x2y2 (4) x2 + y2 = x2y2(2) x + y = xy(1) X- y = xy