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Find the coordinates of point equidistan...

Find the coordinates of point equidistant from axes and lying on the circle `x^2 + y^2 - 6x - 2y + 6 = 0`.

Text Solution

Verified by Experts

`x^2 + y^2 - 6x - 2y + 6=0`
`c: (6/2 , 2/2) = (3,1)`
`r = sqrt(9+1 - 6)= sqrt(4) = 2`
py plotting we get, `|h|= |k|`
`h>0`
when `h=k`
`x^2 + y^2 - 6x -2y + 6=0`
`h^2 + h^2 - 6h - 2h + 6=0`
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