The equation `sinx cosx=2` has:

The equation sqrt3sinx+cosx=4 has

The equation cosx+sinx=2 has

The equation cosx + sinx = 2 has

In the interval [-pi/4,pi/4] the number of real solutions of the equations |[sinx , cosx ,cosx],[cosx, sinx, cosx],[cosx , cosx , sinx]| =0

Solve the equation sinx-cosx= sqrt 2 '

The equation sinx(sinx+cosx)=k has real solutions, where k is a real number, Then

The equation sqrt(3)sinx+cosx=4 has

The equation sqrt(3)sinx+cosx=4 has