If bi=1-ai ,n a=sum(i=1)^n ai ,n b=sum(i...

If `b_i=1-a_i ,n a=sum_(i=1)^n a_i ,n b=sum_(i=1)^n b_i ,t h e nsum_(i=1)^n a_i ,b_i+sum_(i=1)^n(a_i-a)^2=` `a b` b. ` n a b` c. `(n+1)a b` d. `n a b`

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If =1-a_(i),na=sum_(i=1)^(n)a_(i),nb=sum_(i=1)^(n)b_(i), then sum_(i=1)^(n)a_(i),b_(i)+sum_(i=1)^(n)(a_(i)-a)^(2)ab b.-nab c.(n+1)ab d.nab

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