[" (i) "(125)^((1)/(3))," (ii) "(64)^((1)/(6))," (iii) "(25)^((3)/(2))],[" (iv) "(81)^((3)/(4))," (v) "(64)^(-(1)/(2))," (vi) "(8)^((1)/(3))]

Simplify (i) (3^(4))^((1)/(2)) (ii) (64)^((1)/(6)) (iii) ((1)/(3^(4)))^((1)/(2))

Find : quad (i)64^((1)/(2))quad (ii) 32^((1)/(5))quad (iii) 125^((1)/(3))

Evaluate (i) (32)^((1)/(5)) +(-7)^(0) + (64)^((1)/(2)) (ii) (0.00032)^(-(2)/(3)) (iii) ((64)/(125))^(-(2)/(3)) .

(1) (4)/((216)^((2)/(3)))+(1)/((256)^((3)/(4)))+(2)/((243)^((1)/(5))) (ii) ((64)/(125))^((2)/(3))+((256)/(625))^((1)/(4))+((3)/(7))^(0) (iii) ((81)/(16))^((3)/(4))(((25)/(9))^((3)/(2))-:((5)/(2))^(-3)) (iv) ((25)^((5)/(2))times(729)^((1)/(3)))/((125)^((2)/(3))times(27)^((2)/(3))times8^((4)/(3)))

(64)^((1)/(3))[(64)^((1)/(3))-(64)^((2)/(3))]=?

{((216)/(64))^((2)/(3))*(((256)/(81))^(-(1)/(4)))/(((16)/(144))^(-(1)/(2)))}^((1)/(2))

Prove that . (i) [8^(-(2)/(3)) xx 2^((1)/(2))xx 25^(-(5)/(4))] div[32^(-(2)/(5)) xx 125 ^(-(5)/(6)) ] = sqrt(2) (ii) ((64)/(125))^(-(2)/(3)) = (1)/(((256)/(625))^((1)/(4)))+ (sqrt(25))/(root3(64)) = (65)/(16) (iii) [7{(81)^((1)/(4)) +(256)^((1)/(4))}^((1)/(4))]^(4) = 16807 .

Calculate the following . Write them as products. i) (1)/(4) of (1)/(2) ii) (1)/(2) of (1)/(4) iii) (1)/(5) of (1)/(3) iv) (1)/(3) of (1)/(5) v) (1)/(6) . of (1)/(3) vi) (1)/(3) of (1)/(6)

Find: (i) 64^(1/2) (ii) 32^(1/5) (iii) (125)^(1/3)