cos^(2)((pi)/(6)+theta)-sin^(2)((pi)/(6)theta)=

Find the value of cos^(2)((pi)/(6) - (theta)/(2)) - sin^(2) ((pi)/(6)+(theta)/(2)) .

Find the value of the expression 3{sin^(4)((3 pi)/(2)-theta)+sin^(4)(3 pi+theta)}-2{sin^(6)((pi)/(2)+theta)+sin^(6)(5 pi-theta)}

2cos((pi)/(2)-theta)+3sin((pi)/(2)+theta)-(3sin theta+2cos theta)=

The maximum value of 1+sin((pi)/(6)+theta)+2cos((pi)/(3)-theta) for real values of theta is

The maximum value of 1+sin((pi)/(6)+theta)+2cos((pi)/(3)-theta) for real values of theta is

The maximum value of 1+sin((pi)/(6)+theta)+2cos((pi)/(3)-theta) for real values of theta is

sin""((pi)/2+ theta ) * cos (pi- theta ) * cot ""((3pi)/(2)+ theta ) - sin""((pi)/2- theta ) * sin""((3pi)/2 - theta ) * cot ""((pi)/2 + theta ) =

If (3 pi)/(2)

The number of solutions of equation 6cos2 theta+2cos^(2)((pi)/(2))+2sin^(2)pi=0,-pi