If : A+B+C=pi "then" : 1 - sin^(2)""(A)...

If : A+B+C=`pi` `"then" : 1 - sin^(2)""(A)/(2) - sin^(2)""(B)/(2)+ sin^(2)""(C)/(2)=` A)`2cos""(A)/(2) * cos sin ^(2)""(B)/(2) + sin^(2)""(C)/(2)`B)`2 cos ""(B)/(2)* cos ""(B)/(2) * sin""(C)/(2)` C)`2 cos ""(C)/(2)* cos ""(A)/(2) * sin""(B)/(2)` D)`2 cos ""(A)/(2)* cos ""(B)/(2) * sin""(C)/(2)`

A

`2cos""(A)/(2) * cos sin ^(2)""(B)/(2) + sin^(2)""(C)/(2)`

B

`2 cos ""(B)/(2)* cos ""(B)/(2) * sin""(C)/(2)`

C

`2 cos ""(C)/(2)* cos ""(A)/(2) * sin""(B)/(2)`

D

`2 cos ""(A)/(2)* cos ""(B)/(2) * sin""(C)/(2)`

Text Solution

Verified by Experts

The correct Answer is:

D

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