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sin 2A + sin 2B + sin 2 (A-B)= A)4 sin A...

`sin 2A + sin 2B + sin 2 (A-B)=` A)`4 sin A * sin B * sin (A-B)` B)`4 sin A * cos B * cos (A-B)` C)`4 cos A * sin B * cos (A-B)` D)`4 cos A * cos B * sin (A-B)`

A

`4 sin A * sin B * sin (A-B)`

B

`4 sin A * cos B * cos (A-B)`

C

`4 cos A * sin B * cos (A-B)`

D

`4 cos A * cos B * sin (A-B)`

Text Solution

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The correct Answer is:
B
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