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If : cos theta(1) = 2 * cos theta(2), lt...

If : `cos theta_(1) = 2 * cos theta_(2),` ltbr gt `"then" (tan""(theta_(1)-theta_(2))/(2))(tan""(theta_(1) + theta_(2))/(2))=` A)`(1)/(3)` B)`-(1)/(3)` C)1 D)-1

A

`(1)/(3)`

B

`-(1)/(3)`

C

1

D

-1

Text Solution

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The correct Answer is:
B
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