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If : cot theta = (2x(x+1))/(2x+1), "then...

If : `cot theta = (2x(x+1))/(2x+1), "then" : cos theta =` A)`(2x + 1 )/(2x^(2) + 2x + 1 )` B)`(2x )/(2x^(2) + 2x + 1 )` C)`(2x(x+1) )/(2x^(2) + 2x + 1 )` D)`(x+1)/(2x+1)`

A

`(2x + 1 )/(2x^(2) + 2x + 1 )`

B

`(2x )/(2x^(2) + 2x + 1 )`

C

`(2x(x+1) )/(2x^(2) + 2x + 1 )`

D

`(x+1)/(2x+1)`

Text Solution

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The correct Answer is:
C
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