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If x=sin^(2)theta+3 cos theta-2=0, "then...

If `x=sin^(2)theta+3 cos theta-2=0, "then" : cos^(3)theta + sec^(3)theta=`A)18 B)9 C)4 D)`1//4`

A

18

B

9

C

4

D

`1//4`

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