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If y^c=27^@, then: y= (a) ((20pi)/3)^c (...

If `y^c=27^@,` then: `y=` (a) `((20pi)/3)^c` (b) `((20pi)/3)` (c) `((3pi)/20)` (d) `pi/20`

A

`((20pi)/(3))^c`

B

`(20pi)/(3)`

C

`(3pi)/(20)`

D

`(pi)/(20)`

Text Solution

Verified by Experts

The correct Answer is:
C
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