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Given P = (3,-6,10)and PQ = sqrt(17) . I...

Given `P = (3,-6,10)and PQ = sqrt(17)` . If direction cosines of line PQ are ` (-2)/(sqrt(17)),3/(sqrt(17)),(-2)/(sqrt(17))` , then point Q can be

A

`(5,12,-19)`

B

`(1,-3,8)`

C

`(-9,5,12)`

D

`(-2,3,-2)`

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The correct Answer is:
B
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