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int(1)/(sinxsin2x)dx=...

`int(1)/(sinxsin2x)dx=`

A

`(1)/(2)[log(secx+tanx)-cosx]+c`

B

`(1)/(2)[log(secx+tanx)-secx]+c`

C

`(cos3x)/(3)+c`

D

`(1)/(2)[log(cos x-cotx)+secx]+c`

Text Solution

Verified by Experts

The correct Answer is:
A
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