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int(1)/(cosx+secx)dx=...

`int(1)/(cosx+secx)dx=`

A

`(1)/(2sqrt2)log[(sqrt2+sinx)/(sqrt2-sinx)]+c`

B

`(-1)/(2sqrt2)log[(sqrt2-sinx)/(sqrt2+sinx)]+c`

C

`(-1)/(2sqrt2)log[(sqrt2+cosx)/(sqrt2-cosx)]+c`

D

`(1)/(2sqrt2)tan^(-1)[(sinx)/(sqrt2)]+c`

Text Solution

Verified by Experts

The correct Answer is:
A
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