int(1)/(cos2x+sin2x)dx=...

`int(1)/(cos2x+sin2x)dx=`

A

`(1)/(2sqrt2)log[(sqrt2-1+tanx)/(sqrt2+1-tanx)]+c`

B

`(1)/(2sqrt2)log[(sqrt2+1+tanx)/(sqrt2)]+c`

C

`(1)/(sqrt2)log[(sqrt2-1+tanx)/(sqrt2+1-tanx)]+c`

D

`(1)/(2sqrt2)tan^(-1)[(1-tanx)/(sqrt2)]+c`

Text Solution

Verified by Experts

The correct Answer is:

A

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Knowledge Check

int(1)/(cos2x+sin^(2)x)dx=

A

`sinx+c`

B

`cosx+c`

C

`tanx`

D

`cotx`

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