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int(tanax-cotbx)/(1+tanaxcotbx)dx=...

`int(tanax-cotbx)/(1+tanaxcotbx)dx=`

A

`(-1)/(a+b)log{sin[(a+b)x]}+c`

B

`(-1)/(a-b)log{cos[(a-b)x]}+c`

C

`(-1)/(a+b)log{[cos(a+b)x]}+c`

D

`(1)/(a-b)log[secax-secbx]+c`

Text Solution

Verified by Experts

The correct Answer is:
A
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