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int[lim(hrarr0)(sec(x+h)-secx)/(h)]dx=...

`int[lim_(hrarr0)(sec(x+h)-secx)/(h)]dx=`

A

`secx+c`

B

`-secx+c`

C

`secx tan x+c`

D

`-sec xtanx+c`

Text Solution

Verified by Experts

The correct Answer is:
A
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