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int(sinx)/(sinx-cosx)dx=...

`int(sinx)/(sinx-cosx)dx=`

A

`(1)/(2).log(sinx-cosx)+c`

B

`(1)/(2).[log(sinx-cosx)+x]+c`

C

`(1)/(2).log(cosx-sinx)+x+c`

D

`(1)/(2).[log(cosx-sinx)+x]+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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