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intx.sinx.sec^(3)xdx=...

`intx.sinx.sec^(3)xdx=`

A

`(1)/(2)(sec^(2)x-tanx)+c`

B

`(1)/(2)(x.sec^(2)x-tanx)+c`

C

`(1)/(2)(x.sec^(2)x+tanx)+c`

D

`(1)/(2)(sec^(2)x+tanx)+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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